warunki wytrzymałościowe
0 18 Datenblatt pawelszlezak
| Frage | Antworten | |||
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(r)
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(c)
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(g)
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(t)
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(s)
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(w)
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(p)
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6r=Fr/S
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6c=Fc/S
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Ts=Ms/W0
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Tt=F/S
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6g=Mg/Wx
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p=F/S
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ktj
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ko
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kw
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kto
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krc
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